Chemistry · Coordination Compounds

JEE Advanced 2024 — Paper 1 — Question 43

Among the following complexes, the total number of diamagnetic species is _____\_\_\_\_\_ . [Mn(NH3)6]3+,[MnCl6]3−,[FeF6]3−,[CoF6]3−,[Fe(NH3)6]3+\left[\mathrm{Mn}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+},\left[\mathrm{MnCl}_{6}\right]^{3-},\left[\mathrm{FeF}_{6}\right]^{3-},\left[\mathrm{CoF}_{6}\right]^{3-},\left[\mathrm{Fe}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+} and [Co(en)3]3+\left[\mathrm{Co}(\mathrm{en})_{3}\right]^{3+} [Given, atomic number: Mn=25,Fe=26,Co=27\mathrm{Mn}=25, \mathrm{Fe}=26, \mathrm{Co}=27; en =H2NCH2CH2NH2=\mathrm{H}_{2} \mathrm{NCH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2} ]

Answer: 1

Numerical answer — enter this value.

Step-by-step solution

  1. [Mn(NH3)6]+3,n=2\left[\mathrm{Mn}\left(\mathrm{NH}_{3}\right)_{6}\right]^{+3}, \mathrm{n}=2, Paramagnetic

  2. [MnCl6]−3,n=4\left[\mathrm{MnCl}_{6}\right]^{-3}, \quad \mathrm{n}=4, Paramagnetic

  3. [FeF6]−3,n=5\left[\mathrm{FeF}_{6}\right]^{-3}, \quad \mathrm{n}=5, Paramagnetic

  4. [CoF6]−3,n=4\left[\mathrm{CoF}_{6}\right]^{-3}, \quad \mathrm{n}=4, Paramagnetic

  5. [Fe(NH3)6]+3,n=1\left[\mathrm{Fe}\left(\mathrm{NH}_{3}\right)_{6}\right]^{+3}, \mathrm{n}=1, Paramagnetic

  6. [Co(en)3]+3,n=0\left[\mathrm{Co}(\mathrm{en})_{3}\right]^{+3}, \mathrm{n}=0, Diamagnetic

Answer key and solution verified before publishing.

Practise Coordination Compounds

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Exam
JEE Advanced 2024
Paper
Paper 1
Subject
Chemistry
Chapter
Coordination Compounds
Topic
Theories of Bonding in Coordination Compounds
Among the following complexes, the total number of diamagnetic… | JEE Advanced 2024 PYQ with Solution · DhiX AI