Physics · Fluid Mechanics

JEE Advanced 2020 — Paper 2 — Question 3

A hot air balloon is carrying some passengers, and a few sandbags of mass 1 kg each so that its total mass is 480 kg . Its effective volume giving the balloon its buoyancy is V. The balloon is floating at an equilibrium height of 100 m . When N number of sandbags are thrown out, the balloon rises to a new equilibrium height close to 150 m with its volume V remaining unchanged. If the variation of the density of air with height hh from the ground is ρ(h)=ρ0e−hh0\rho(h)=\rho_{0} e^{-\frac{h}{h_{0}}}, where ρ0=1.25 kg m−3\rho_{0}=1.25 \mathrm{~kg} \mathrm{~m}^{-3} and h0=6000 mh_{0}=6000 \mathrm{~m}, the value of N is ____\_\_\_\_

Answer: 4

Numerical answer — enter this value.

Step-by-step solution

480−N480=ρ2ρ1\frac{480-N}{480}=\frac{\rho_{2}}{\rho_{1}}

1−N480=e−(150−1006000)1-\frac{N}{480}=e^{-\left(\frac{150-100}{6000}\right)}

⇒1−N480=1−5600\Rightarrow 1-\frac{N}{480}=1-\frac{5}{600}

N=4\mathrm{N}=4

Answer key and solution verified before publishing.

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Exam
JEE Advanced 2020
Paper
Paper 2
Subject
Physics
Chapter
Fluid Mechanics
Topic
Buoyancy and Archimedes' Principle
A hot air balloon is carrying some passengers, and a few sandbags of… | JEE Advanced 2020 PYQ with Solution · DhiX AI